Math // Algebra
Factorising Expressions
Factorise algebraic expressions by taking out common factors — identify the highest common factor of all terms and write the expression as a product, e.g., 6x + 9 = 3(2x + 3)
Quick check
Can the learner look at an expression like "6x + 9" and rewrite it with the common factor taken out — as "3(2x + 3)"?
Ask this to see whether the topic is secure.
Topic // Mastery
What mastery looks like
- Identify the highest common factor of all terms in an expression
- Write the factorised form as a product of the HCF and a bracket
- Check factorisation by expanding the brackets back out
Topic // Map
Where this fits
- RequiredMust come first
- HelpfulHelps, but not essential
Before this
1 topic- Expanding Single BracketsRequired
Algebra // Ages 11 to 13
Factorising is the reverse of expanding — students need expanding fluency first
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Factorising Expressions
Ages 12 to 13 // Method
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Topic // Research-informed
Teaching notes
From the Marble Skill Taxonomy. These notes have not been validated in classrooms, so treat them as a starting point for your own judgement.
The approach
Factorising by common factors is the inverse of expanding: rewrite a sum as a product by pulling out the highest common factor (HCF) of every term, leaving a bracket with no remaining common factor, e.g. 6x+9 = 3(2x+3). Teach it alongside expanding, use a reverse area/array model (arrange the terms into a rectangle whose common side is the factor; the HCF gives the single rectangle with the LARGEST common side — the most compact block, not the long thin strip a smaller factor leaves), and always check by expanding the answer back. Signature errors are taking a factor that is not the highest (incomplete factorisation) and dropping or mis-dividing a term. Extend 'common factor' to a shared letter, e.g. x²+3x = x(x+3).
Common misconceptions
- Takes a common factor that is not the HIGHEST: 12x+8 → 2(6x+4) instead of 4(3x+2) — 'factorised' but not fully.
- Drops or fails to divide a term: 6x+9 → 3(2x) or 3(2x+9) (the 9 not divided).
- Only spots numeric factors and misses a common variable: x²+3x left unfactorised or written 3(x²)... .
- Does not check by expanding, so an incorrect factorisation goes unnoticed.
- Confuses factorising (→ product) with simplifying/collecting (→ fewer terms).
Useful representations
- Reverse area/array model (terms arranged into a rectangle; common side = factor)
- HCF via prime factors or factor lists of the coefficients
- Expand-back check (product → sum)
- Side-by-side expand/factorise pair showing the inverse relationship
Teaching practices
- Teach it as the reverse of expanding — do an expansion, then run it backwards — and always CHECK by expanding the factorised form.
- Find the HCF of the coefficients (and any common variable) first; stress 'fully' means no common factor is left inside the bracket.
- Use the reverse area/array model: the terms tile a rectangle whose common side is the factor; the HCF gives the neatest single rectangle.
- Divide EVERY term by the factor — 6x÷3 and 9÷3 — and write each result inside the bracket; a dropped term is the classic slip.
- Extend to a common variable factor, e.g. x²+3x = x(x+3), so 'common factor' includes letters, not just numbers.
Activities to try
- 1
Build the rectangle with the largest common side: the reverse area model
Why it works: The highest common factor is 'the biggest common side that leaves nothing left to share', so fully factorised means no common factor remains inside the bracket; factorising and expanding are inverse moves.
- Take the tiles for 12x + 8 (twelve x-tiles and eight unit tiles) and try to arrange them into one solid rectangle.
- First try a common side of 2: notice the result is a long 2-by-(6x+4) strip. Check whether each row could be split again into equal parts — it can, because 6x and 4 both still divide by 2, so the strip can be regrouped into a taller rectangle. That means 2 is a common factor but not the highest, so 2(6x+4) is not fully factorised.
- Now try a common side of 4: the tiles form a compact 4-by-(3x+2) block with nothing left to share, giving 12x + 8 = 4(3x + 2).
- Divide EVERY original term by the factor you pulled out (12x÷4 = 3x and 8÷4 = 2) and write each result inside the bracket.
- Use an 'expand back' action to re-spread the rectangle into 12x + 8 and confirm the product equals what you started with.
- 2
Factorise then expand-back: the routine check
Why it works: A factorisation is only complete when the bracket shares no further common factor, and expanding back is the way to catch dropped or mis-divided terms.
- Given 6x + 9, find the HCF of 6 and 9 using prime factors or factor lists, then write 6x+9 = 3(2x+3), dividing each term by 3.
- Immediately expand your product back out and confirm it returns the original expression.
- Decide whether a given bracket is fully factorised: is 2(6x+4) fully factorised? Explain how you can tell.
- Explain in your own words what factorising is 'undoing'.
- 3
Annotated worked example: where each number comes from
Why it works: Every term in the sum maps to factor × a term in the bracket, which is why no term may be dropped or left undivided.
- Study the worked line 6x + 9 = 3(2x + 3) and reveal, one piece at a time, where the 3, the 2x and the 3 inside the bracket each come from (3 is the HCF; 2x = 6x÷3; 3 = 9÷3).
- Trace each original term to its matching entry inside the bracket, confirming no term was dropped.
Topic // Standards
Curriculum standards
- Common Core State Standards for Mathematics
- 7.EE.1
- The national curriculum in England: Key stages 1 and 2 framework document
- KS3.Maths.Alg.4c
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