Science // Forces & Motion
Speed & Distance-Time Graphs
Calculate average speed using the equation speed = distance ÷ time, represent journeys on distance-time graphs, and interpret gradient as speed and flat sections as stationary periods
Quick check
If the learner tracked a cycle ride on a map and knew how far they went and how long it took, could they calculate the average speed — and then sketch a rough graph showing the journey including a stop for lunch?
Ask this to see whether the topic is secure.
Topic // Mastery
What mastery looks like
- Uses speed = distance ÷ time to calculate average speed with correct units (m/s, km/h)
- Draws a distance-time graph for a given journey with correct axes and labels
- Reads a distance-time graph to determine speed, stopping points, and direction of travel
- Identifies which section of a distance-time graph represents the fastest speed
Topic // Map
Where this fits
- RequiredMust come first
- HelpfulHelps, but not essential
Before this
2 topics- Reading Distance-Time GraphsRequired
Forces & Motion // Ages 10 to 13
Calculating speed and representing journeys on distance-time graphs requires being able to plot and read these graphs
- Compound UnitsHelpful
Mathematics // Ratio & Proportion // Ages 11 to 14
Calculating speed as distance ÷ time applies compound-unit thinking from Math
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Speed & Distance-Time Graphs
Ages 11 to 12 // Concept
Leads to
1 topic- Relative MotionRequired
Forces & Motion // Ages 11 to 12
Relative motion requires first being able to calculate and describe speed — without that foundation, comparing speeds of different observers is abstract
Topic // Research-informed
Teaching notes
From the Marble Skill Taxonomy. These notes have not been validated in classrooms, so treat them as a starting point for your own judgement.
The approach
For ages 11–12, teach average speed as a proportional rate linking distance and time, built up from distance = speed × time ('m/s means metres travelled each second') before introducing speed = distance ÷ time. The central threshold is that average speed = TOTAL distance ÷ TOTAL time, including any stationary periods — not the mean of the separate speeds (the mean is only correct when equal time is spent at each speed). Use double number lines and ratio tables to expose the proportional structure and support prediction, connect the calculation to the gradient of a distance-time graph (a single leg's speed is its segment gradient; the whole-journey average is the start-to-end chord gradient), and confront the 'mean of the speeds' and 'ignore the stop' errors directly. A journey-building activity with live, synchronised feedback is the richest approach; a quiz consolidates the procedure; a worked-example reference card scaffolds a single case.
Common misconceptions
- Calculating average speed as the mean of the individual speeds rather than total distance ÷ total time (Third Space Learning).
- Forgetting to include stationary periods in the total time when finding average speed.
- Reading a value off the vertical axis and calling it the speed instead of finding the gradient.
- Treating the formula triangle as the whole concept — procedural recall that blocks proportional reasoning (Susac et al., Phys. Rev. PER).
- Language slips: 'constant speed' read as 'always moving', 'steady speed' as 'not too fast'; conflating distance with displacement (Oak National Academy).
Useful representations
- Double number line linking distance and time (NCETM) — the central proportional model
- Ratio table for distance:time, scaled by a functional multiplier
- Distance-time graph with gradient = average speed
- The speed-distance-time 'formula triangle' (a memory aid, used with caution, not as a substitute for reasoning)
- Unit unpacking: m/s as 'metres each second', km/h, mph
Teaching practices
- Teach distance = speed × time before speed = distance ÷ time; anchor on 'm/s = the number of metres travelled each second' (Oak National Academy).
- Use double number lines and ratio tables (NCETM) to make the proportional relationship visible — e.g. scaling distance and time together to predict how far in a new time — rather than relying solely on the formula triangle, which can short-circuit reasoning.
- Define average speed explicitly as total distance ÷ total time, including stopped periods; give journeys with stops so the 'mean of the speeds' error is confronted.
- Connect the calculation to the graph: average speed of a straight segment IS its gradient; have pupils compute it both ways and reconcile.
- Use precise language — qualify 'constant'/'steady' with a value ('a constant speed of 4 m/s') and always state units; keep distance distinct from displacement.
- Use predict-then-calculate tasks (estimate the speed, then compute) and real contexts (cyclists, cars) to keep the abstraction grounded.
Activities to try
- 1
Build a journey and watch the average speed update
Why it works: Average speed = total distance ÷ total time, and stopped seconds still count in the denominator. With two equal-time legs the mean of the two speeds (here 6 m/s) is genuinely correct; but inserting a stop adds time without adding distance, so the average drops below it — showing that total time, including stops, is what matters. Speed is a proportional rate you can scale to predict new distances and times.
- Assemble a trip from segments, choosing a speed for each leg; for the core demonstration use two legs of EQUAL DURATION (e.g. a leg at 8 m/s then an equal-time leg at 4 m/s), and insert optional STOP blocks of a chosen duration.
- Before inserting a 20-second stop between the two equal-duration legs, predict the average speed over the whole trip and write down your reasoning.
- Insert the stop and observe how the average-speed readout changes; note whether it rose, fell, or stayed the same, and explain why.
- Use a double-number-line widget beside the journey to predict: 'keeping this leg's speed, how far would you travel in 10 seconds?' by scaling distance and time together.
- Attempt a challenge: adjust the journey to hit a target average speed when one stop is forced into the trip.
- 2
Consolidate the calculation and graph reading
Why it works: The speed = distance ÷ time procedure can be applied reliably with correct units, average speed over a whole journey is not the mean of the leg speeds, and the gradient of a straight distance-time segment gives that leg's speed.
- Fill in the missing quantity for distance = speed × time and for speed = distance ÷ time rearrangements, attaching correct units each time.
- Read the speed of a straight distance-time graph segment by computing its gradient (distance change ÷ time change).
- For a multi-leg journey that includes a stop, choose the correct average speed from options that include the 'mean of the speeds' answer, and justify the choice.
- Order several graph sections from slowest to fastest by comparing their gradients.
- 3
Walk through a worked example as a reference card
Why it works: A single average-speed calculation follows a fixed, checkable sequence: identify total distance, identify total time, divide, and attach units.
- Step through one worked journey: reveal the total distance, reveal the total time, then reveal the division and the resulting speed with its units.
- Note the unit reminder at each step (metres ÷ seconds = metres per second).
- Use the card as a recap aid when stuck on a later calculation.
Topic // Standards
Curriculum standards
- Next Generation Science Standards (NGSS) Middle School
- MS-PS2-2
- The national curriculum in England: Key stages 1 and 2 framework document
- KS3.Sci.Phys.MotionAndForces.1KS3.Sci.Phys.MotionAndForces.2
Science // Forces & Motion
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